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0001 <sect1 id="ai-blackbody"> 0002 0003 <sect1info> 0004 0005 <author> 0006 <firstname>Jasem</firstname> 0007 <surname>Mutlaq</surname> 0008 <affiliation><address> 0009 </address></affiliation> 0010 </author> 0011 </sect1info> 0012 0013 <title>Blackbody Radiation</title> 0014 <indexterm><primary>Blackbody Radiation</primary> 0015 <seealso>Star Colors and Temperatures</seealso> 0016 </indexterm> 0017 0018 <para> 0019 A <firstterm>blackbody</firstterm> refers to an opaque object that 0020 emits <firstterm>thermal radiation</firstterm>. A perfect 0021 blackbody is one that absorbs all incoming light and does not 0022 reflect any. At room temperature, such an object would 0023 appear to be perfectly black (hence the term 0024 <emphasis>blackbody</emphasis>). However, if heated to a high 0025 temperature, a blackbody will begin to glow with 0026 <firstterm>thermal radiation</firstterm>. 0027 </para> 0028 0029 <para> 0030 In fact, all objects emit thermal radiation (as long as their 0031 temperature is above Absolute Zero, or -273.15 degrees Celsius), 0032 but no object emits thermal radiation perfectly; rather, they are 0033 better at emitting/absorbing some wavelengths of light than others. 0034 These uneven efficiencies make it difficult to study the interaction 0035 of light, heat and matter using normal objects. 0036 </para> 0037 0038 <para> 0039 Fortunately, it is possible to construct a nearly-perfect blackbody. 0040 Construct a box made of a thermally conductive material, such as 0041 metal. The box should be completely closed on all sides, so that the 0042 inside forms a cavity that does not receive light from the 0043 surroundings. Then, make a small hole somewhere on the box. 0044 The light coming out of this hole will almost perfectly resemble the 0045 light from an ideal blackbody, for the temperature of the air inside 0046 the box. 0047 </para> 0048 0049 <para> 0050 At the beginning of the 20th century, scientists Lord Rayleigh, 0051 and Max Planck (among others) studied the blackbody 0052 radiation using such a device. After much work, Planck was able to 0053 empirically describe the intensity of light emitted by a blackbody as a 0054 function of wavelength. Furthermore, he was able to describe how this 0055 spectrum would change as the temperature changed. Planck's work on 0056 blackbody radiation is one of the areas of physics that led to the 0057 foundation of the wonderful science of Quantum Mechanics, but that is 0058 unfortunately beyond the scope of this article. 0059 </para> 0060 0061 <para> 0062 What Planck and the others found was that as the temperature of a 0063 blackbody increases, the total amount of light emitted per 0064 second increases, and the wavelength of the spectrum's peak shifts to 0065 bluer colors (see Figure 1). 0066 </para> 0067 0068 <para> 0069 <mediaobject> 0070 <imageobject> 0071 <imagedata fileref="blackbody.png" format="PNG"/> 0072 </imageobject> 0073 <caption><para><phrase>Figure 1</phrase></para></caption> 0074 </mediaobject> 0075 </para> 0076 0077 <para> 0078 For example, an iron bar becomes orange-red when heated to high temperatures and its color 0079 progressively shifts toward blue and white as it is heated further. 0080 </para> 0081 0082 <para> 0083 In 1893, German physicist Wilhelm Wien quantified the relationship between blackbody 0084 temperature and the wavelength of the spectral peak with the 0085 following equation: 0086 </para> 0087 0088 <para> 0089 <mediaobject> 0090 <imageobject> 0091 <imagedata fileref="lambda_max.png" format="PNG"/> 0092 </imageobject> 0093 </mediaobject> 0094 </para> 0095 0096 <para> 0097 where T is the temperature in Kelvin. Wien's law (also known as 0098 Wien's displacement law) states that the 0099 wavelength of maximum emission from a blackbody is inversely 0100 proportional to its temperature. This makes sense; 0101 shorter-wavelength (higher-frequency) light corresponds to 0102 higher-energy photons, which you would expect from a 0103 higher-temperature object. 0104 </para> 0105 0106 <para> 0107 For example, the sun has an average temperature of 5800 K, so 0108 its wavelength of maximum emission is given by: 0109 0110 <mediaobject> 0111 <imageobject> 0112 <imagedata fileref="lambda_ex.png" format="PNG"/> 0113 </imageobject> 0114 </mediaobject> 0115 </para> 0116 0117 <para> 0118 This wavelengths falls in the 0119 green region of the visible light spectrum, but the sun's continuum 0120 radiates photons both longer and shorter than lambda(max) and the 0121 human eyes perceives the sun's color as yellow/white. 0122 </para> 0123 0124 <para> 0125 In 1879, Austrian physicist Stephan Josef Stefan showed that 0126 the luminosity, L, of a black body is proportional to the 4th power of its temperature T. 0127 </para> 0128 0129 <para> 0130 <mediaobject> 0131 <imageobject> 0132 <imagedata fileref="luminosity.png" format="PNG"/> 0133 </imageobject> 0134 </mediaobject> 0135 </para> 0136 0137 <para> 0138 where A is the surface area, alpha is a constant of proportionality, 0139 and T is the temperature in Kelvin. That is, if we double the 0140 temperature (e.g. 1000 K to 2000 K) then the total energy radiated 0141 from a blackbody increase by a factor of 2<superscript>4</superscript> or 16. 0142 </para> 0143 0144 <para> 0145 Five years later, Austrian physicist Ludwig Boltzman derived the same 0146 equation and is now known as the Stefan-Boltzman law. If we assume a 0147 spherical star with radius R, then the luminosity of such a star is 0148 </para> 0149 0150 <para> 0151 <mediaobject> 0152 <imageobject> 0153 <imagedata fileref="luminosity_ex.png" format="PNG"/> 0154 </imageobject> 0155 </mediaobject> 0156 </para> 0157 0158 <para> 0159 where R is the star radius in cm, and the alpha is the 0160 Stefan-Boltzman constant, which has the value: 0161 0162 <mediaobject> 0163 <imageobject> 0164 <imagedata fileref="alpha.png" format="PNG"/> 0165 </imageobject> 0166 </mediaobject> 0167 </para> 0168 0169 </sect1>